0
\$\begingroup\$

What is the formula for Vdc of a Center tapped full wave rectifier?

Is it

0.636*Vac - Vk (where Vk is the potential drop across a single diode. Assume both diodes have the same cutoff voltage)

or is it

0.636*Vac - 2Vk

It's not given anywhere in my textbook and I couldn't find it on the internet either. Logically the first one makes more sense to me because for every half-cycle, input voltage is across just one diode unlike in a full wave bridge rectifier where the input voltage is across two diodes.

\$\endgroup\$
0
\$\begingroup\$

2*Vsecondary/Pi - Vk or as you put it 0.636*Vac - Vk.

\$\endgroup\$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.