1
\$\begingroup\$

I am trying to get my PC speakers to be controlled by my arduino. I've taken apart the control and it seems very straight forward, just need a few questions about subbing the manual pots for digital ones.

Volume circuit looks like this (R/L for right and left channels)

    R Aux -> Pot Leg 1 -> Out Pot Leg 3 -> R Audio Out
    L Aux -> Pot Leg 2 -> Out Pot Leg 4 -> L Audio Out

All other POT contacts are grounded and it's a B10K pot.

Why are these split by channel? Isn't a standard 3 terminal pot the same? Or is it to keep the audio in R and L channel's seperate?

Is there any weird issue I'll run into subbing out this pot for a digital one? Or would another 4/6 contact digital 10K pot do just fine? Are their power requirements (voltage/heat dissipation) i need to watch out for?

Thank you! Just learning speaker wiring.

\$\endgroup\$
0
\$\begingroup\$

You ought to consider that the volume pot is logarithmic and this might mean that the digipot's resolution needs to be quite high to get a non granular change in volume when you control it.

\$\endgroup\$
  • \$\begingroup\$ Digital pots come in log flavo[u]r too. \$\endgroup\$ – Spehro Pefhany Sep 28 '14 at 3:01
  • \$\begingroup\$ Gotcha, what about power tolerances though? Any typical values in speakers? \$\endgroup\$ – Smanger Sep 28 '14 at 18:06
  • \$\begingroup\$ @Smanger - I don't understand your comment - are you believing the pots connect direct to the speakers? This would be incorrect almost certainly. \$\endgroup\$ – Andy aka Sep 28 '14 at 18:53
  • \$\begingroup\$ Ah i understand, so it goes from the AUX line to the pot to the amp out to the speakers.. Thanks. I assume any pot will do then, since the voltage/current from headphones should be minimal. \$\endgroup\$ – Smanger Sep 29 '14 at 6:48

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.