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I've looked extensively about this topic, and can't find any answers. Hopefully someone on here can help.

I live in Texas and have 120V power in my house. I'm using a lamp touch dimmer to dim two ceiling boxes in my kitchen. The sensor wire goes to two metal plates mounted under the lip of my island. The dimmer works GREAT with incandescent bulbs. But my wife picked out these beautiful low voltage (12V AC) halogen lamps for over the island. There are two, and each lamp has its own magnetic low voltage transformer in the ceiling box. The dimmer will not illuminate the halogens at all by themselves, but it will illuminate and works perfectly if I put any incandescent bulb in parallel with them...

Is there a way to put a resistor on the load side of the dimmer to trick the dimmer into thinking there is an incandescent bulb there that I can hide in the box with the dimmer module? If so, how much resistance and how do I verify it will handle the voltage?

I have tested many bulbs in parallel and the lowest wattage bulb I can find is 15 Watts and only 82 Ohms and works great. I tried a 1KOhm resistor and it worked on level one dimming, but popped on level two and took out my first 150 watt dimmer.

One idea is to simply put a 15 watt bulb in the attic, but I figured there has to be a better solution.

The dimmer is made by Westek, I currently own the 150 watt and the 300 watt dimmer. Both do the same thing even though the 300 watt advertises that it works on halogen as well. All connections are in approved boxes and have cover plates over them. This has been inspected by the county and signed off on, minus the resistor obviously... So I'm not concerned about that.

Clarification: The Halogen lamps that come with the transformers clearly state that they are dimmable with a standard incandescent dimmer. The touch dimmers clearly state that they work with incandescent or halogen lights. I am not trying to make an item that's not designed to work with another item. I am simply trying to create a larger load so the "old dimmer design" will work with a much more efficient light.

Update: After researching some more and actually doing my own resistance calculations, I decided to try 5 33KOhm resistors wired in parallel, thus giving me 2.1 calculated watts of dispersed power. And the dimmer works, but only two stages. If I put the 2.1 watts of resistors with the 15 watt bulb, it works with all three stages of dimming. Tomorrow I will go buy more 33KOhm resistors and add another 2 watts of power to the circuit and see if I gain my level 3 brightness, or lack of dimming setting on my dimmer. Wish me luck. Either way, we have progress!

*Update #2 Here is the latest... I put (10) 33KOhm resistors in parallel and added a 1 amp fuse rated for 250V in between the load and the dimmer. It works great for short amounts of time. After 10 minutes, the wires on the resistors would heat up to 250*F, the resistors themselves were only 90*F... I did not trust this in my walls, thus it was removed and replaced with a 3 Watt 120V incandescent bulb that fits in a surface mount socket with a lens cover. The bulb gets to about 120*F but is outside the wall in the air conditioned room. My amp clamp doesn't read the load on the resistors cause it's far less than .1 amps. The total load on the dimmer is .6 amps. My calculated total power on the resistors was 4.3636 Watts, and the total calculated load was 3.6 milliamps. I truly could have spent another week finding a better resistor than what was at radio shack and made this work, but I feel better with the indicator light on the wall plate. Thanks for everyone's help!!!*

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  • \$\begingroup\$ Although the theory is certainly EE, it seems you want a working solution. Therefore diy.stackexchange.com might be able to help you better. \$\endgroup\$ – David Oct 2 '14 at 18:26
  • \$\begingroup\$ You can get dimmable transformers for lighting. \$\endgroup\$ – Andrew Morton Oct 2 '14 at 19:18
  • \$\begingroup\$ @Andrew This would not solve my dimming issue. MY design allows me to run a sensor wire to my island so there is no AC voltage or switch or any contactors on the island. I really like the dimmer's function, I just need it to work with the low voltage halogens I have... \$\endgroup\$ – Bruce Burkhardt Oct 2 '14 at 19:44
  • \$\begingroup\$ The dimmers that advertise halogen/fluorescent support are generally a bit smarter and do slow start and proper zero crossing detection. They aren't likely to work with a transformer that doesn't advertise it is dimmable. \$\endgroup\$ – David Oct 2 '14 at 19:51
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    \$\begingroup\$ @david The transformers are dimmable, the problem is that no one makes a touch dimmer that works on CFLs or low voltage magnetic transformers. The dimmer I have is intended to see a load to dim and the transformers don't load the dimmer enough to make it work. If I add a load in parallel to the transformers, the dimmer works just fine. This is a scenario where the products I have to make the scenario work, aren't exactly supposed to work together, but could with the right knowledge. I just don't have that knowledge right now... \$\endgroup\$ – Bruce Burkhardt Oct 2 '14 at 19:56
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An 82 ohm resistor would dissipate about 175 watts; indeed, a 15 watt bulb may dissipate that much power briefly. Something the size of a 15-watt bulb that dissipates 175 watts is going to get very hot, however, and when tungsten gets hot its resistance increases by an order of magnitude. You may have been expecting your 1K resistor to dissipate about 1.5 watts, but in practice it would have dissipated about 17.5 initially. Most resistors don't nicely increase their resistance with temperature the way a lightbulb filament does, however, so your resistor may have continued to dissipate that much power until it melted, whereupon its resistance might have actually decreased, causing it to try to dissipate even more power, until things went downhill very severely.

I would suggest that you might consider a Christmas decoration that's designed for a C7 bulb; such bulbs draw about 1 Watt. If you wanted to use a resistor that drew less power, two 33K resistors half-watt resistors in series would probably be reasonably safe if they were somewhat ventilated (the resistors should dissipate less than 1/8 watt each, but half-watt resistors should be used so that in case one fails shorted the other would be able to handle the 0.44-watt fault power) but might not let through enough power to operate the touch switch (if it does work, keep adding 33K resistors until it doesn't work reliably, and then remove one). The fact that incandescent bulbs have a much lower resistance when cold than when heated allows a much smaller energy-wasting element to be used for a given application than would otherwise be necessary.

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  • \$\begingroup\$ This didn't work. I tried the 33K resistors (2) in series, and they didn't create enough load on the dimmer to allow it to even try... Would you go lower? Trial and error? Or should I just cave and go find a small incandescent bulb. I really don't want a bulb, cause they create so much heat!!! But I can get 3 watt T3 1/4 bayonet bulbs, just not certain they would draw enough load to help... I know a 15 watt bulb works... \$\endgroup\$ – Bruce Burkhardt Oct 2 '14 at 19:38
  • \$\begingroup\$ 33k or 33ohm? 33k would definitely not work. \$\endgroup\$ – Dave Oct 2 '14 at 19:50
  • \$\begingroup\$ @Dave, 33K like supercat suggested \$\endgroup\$ – Bruce Burkhardt Oct 2 '14 at 20:06
  • \$\begingroup\$ @BruceBurkhardt: A C7 Christmas bulb is about one watt. Resistors are going to generate more heat for any given level of conductance when in the "odd" state. It might be safe to use a larger number of resistors with a smaller total resistance (things should be engineered so that any single resistor could fail shorted without overheating the others; if you use two half-watt resistors, that means 33K each. Using five 4.7K quarter-watt resistors would probably be safe as well (they'll dissipate 0.12 watts each when they're working, or 0.2 watts if one fails). \$\endgroup\$ – supercat Oct 2 '14 at 20:35
  • \$\begingroup\$ @BruceBurkhardt: Using five resistors, however, isn't really going to buy you much versus using a C7 bulb. You'd be dissipating over half a watt, and run a higher risk of a nasty progressive failure (e.g. if a power surge clobbers four resistors, the remaining one would have to dissipate three watts), meaning you should probably add a fuse as well. \$\endgroup\$ – supercat Oct 2 '14 at 20:38

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