As I learned before, the peak voltage value of two combined sinusoidal signals is the sum of the two amplitudes, for example, \$0.6\sin(ax) + 0.8 \cos(bx)\$ can be \$+1.4\$V or \$-1.4\$V. Would it be the case for the noise?
For example, if now the output noise signal is \$1\$Vpp and my desired signal is \$1\$V at \$1\$kHz. Would the peak value of output become \$+2\$V or \$-2\$V?
One more question: If the answer of the above question is yes, would an amplifier which limits its output to the range \$\pm1.5\$V saturate at that time?