I am measuring the voltage drop on a 1MΩ resistor with an oscilloscope, and as I understand to get accurate readings I should compensate the internal impedance of my measurement device for such a high value resistor.
It's a Tektronix TDS2024C oscilloscope, from the manual I know that it has a 1MΩ internal impedance and I'm using a 10x attenuation probe, which should have a 9MΩ resistance. According to everything I read that should add to a 10MΩ internal impedance, even though I'm not quite sure why and would like to know it a little more accurately.
So, two questions:
- Are there any simple methods to measure the input impedance of an oscilloscope accurately instead of taking the word of the manufacturer?
- How does the input impedance add to 10MΩ anyways, if the internal resistance isn't connected in series? Shouldn't it form a voltage divider for 0.91MΩ? Schematic below: