1
\$\begingroup\$

There is a quantity called current leakage which has always confused me. By reading various definitions, it seems to be the current flowing through the ground circuit of a device (whether this be an actual safety circuit for class I appliances, or the human body in the case of class II appliances). Some sources say it's the current flowing through the insulation, and when a human contacts a conductive part; the current leakage flows through the human.

My question is; how exactly does this quantity come into play when compared to the typical way of thinking about electric shocks (the applied voltage divided by resistance, then refer to a table of safe current limits)

I found this post interesting What is the right way to understand the behaviour of shocking voltage?

Considering all this information, something doesn't feel quite right. The issues I have are the following : 1) Is current leakage simply the maximum current that would pass through the body? (If that's the case, how would you work out the actual current passed through the body?)

2) How is current leakage related to the 'applied voltage' from above? If currentleakage x insulation resistance = 'applied voltage', this would lead to ridiculous results such as dying if you touch plastic.

3) can the body be treated simply as a parallel resistor? I've followed through with some of these calculations and the numbers don't make sense. And current leakage seemed to be made redundant/irrelevant even though it's clearly not due to PAT testing.

4)What ever happened to the law of 'current is the same in series'? When you touch an insulator, you are in series with it (if you are connected to the ground)?

\$\endgroup\$
1
\$\begingroup\$

Leakage currents are usually currents that are capacitively coupled to (for example) a chassis. If a user could touch the chassis, AND the chassis is not grounded, then the potential on the chassis could cause a current to flow in the user and cause a shock. Remember, two conductors separated by an insulator form a capacitor and it will conduct AC current according to I=C*dv/dt.

One example of this is the Y-capacitors used in power supplies for EMI filters. Both sides of the line are connected through capacitors to chassis ground to filter the high frequency conducted EMI. Now, if the ground prong on the AC cord is not connected (for whatever reason) the Y-Caps will cause the potential on the chassis to rise and you can feel a tingle if you get between the chassis and ground.

Regulatory requirements are such that the Y capacitors should not pass enough current to cause danger, but there are other potential paths for leakage currents as well. A switching transistor mounted with an insulator to a grounded heatsink also capacitively couples currents into the chassis.

There's no violation of Kirchoff's current law in any of this.

\$\endgroup\$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.