I have a capacitor C which changes with time. Now I want to measure the varying capacitance as a voltage function, so I need to design a circuit for that. My motivation around the problem is that, I want to apply a constant voltage to the capacitor always, so if I have a change in capacitance, I will have a change in the current of the circuit.
Q=CV, so for constant voltages dQ/dt=VdC/dt; so if I take that current and pass it through a current to voltage changer and then pass it through an integrator, I might get my output voltage as a linear function of capacitance, so I have set up the following circuit for the same.
My only apprehension is that since the output impedance of op-amps are very low, hence my initial voltage follower circuit might sink my information current completely and I might be left with no current to process in the 2nd and third stages. Am I being logical here or am I being mislead somewhere, if I am correct in my assumption, please give me some suggestions to work around the process or suggest a different circuit which I might find useful.