0
\$\begingroup\$

I'm making a pre-amplifier for my 9mm electret microphone to be read by an Arduino. Here's the schematic:

pre-amp schematic

Note that the resistor I used connected to the output is 1Meg. My supply voltage is 5V.

Initially I used LM358 as the op-amp. When I plotted the output it seems to be normal -centered around 2.5V with a bit of noise (my plot range is 0 to 5V). But when detecting loud sounds, the output gets clipped to ~3.7V.

Because of that I decided to switch the op-amp with a rail to rail AD8051 instead. Wiring with corresponding pinout from its data-sheet and using the same resistors, capacitor and mic. Now the output I get is somehow centered at 0V and the signal seems to be amplified more than the last time.

Why did this happen and how do I get the output to center back at 2.5V? aren't op-amps interchangeable without having to change resistor values?

\$\endgroup\$
2
  • 1
    \$\begingroup\$ Double-check your new wiring. You must have made an error somewhere. \$\endgroup\$
    – Dave Tweed
    Commented Nov 22, 2014 at 17:31
  • \$\begingroup\$ Your cap might be backwards (isn't the MIC voltage < 2.5V?) but that is not the cause. It can't be 'centered at 0V' if you have no negative supply. Wiring problem (or measurement problem) is suspected. \$\endgroup\$ Commented Nov 22, 2014 at 17:32

1 Answer 1

5
\$\begingroup\$

The input bias current of the AD8051 might be as high as a couple of micro amps and this doesn't sound much but, through a 1Mohm feedback resistor, this will generate a dc error of 2 volts on the output. Note that with the +input seeing a DC resistance of about 5kohm, the same bias current will produce an error of about 10mV. I would suggest equalizing resistances in both inputs but you are going to start to run into noise problems with so many 1Mohms in your circuit I suspect.

Try something more like and AD8605 (input bias current less than 50pA). Alternatively consider the non-inverting topology: -

enter image description here

Not shown is the electret bias resistor of 10kohms and, also, Rin is not needed. The non-inverting input is biased at mid-rail by the two 100k resistors and these, for a device like the AD8051 can be as low as a couple of kohms thus ensuring bias currents don't create a large offset voltage. RF and R1 set the gain and a gain of 1,000 can be achieved with R1 = 100 ohms and RF = 100,000 ohms - this means the feedback resistance is one-tenth of what you had and the offset it introduces will accordingly be one-tenth at about 0.2 volts on the output. Ci in the feedback area will need to be much bigger than 0.1uF because R1 is now only 100ohms - something like 47uF. Ci on the input leg can be 10uF.

\$\endgroup\$
1
  • \$\begingroup\$ I tried using your schematic and it's now working. Thanks! :) \$\endgroup\$
    – Charles V.
    Commented Dec 7, 2014 at 6:34

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.