For example, assume you have this transistor with a grounded emitter:
Since we are dealing with a saturation mode, \$v_{ce} = 0.2 \$ making the drop across the resistor 9.8 v. The current going through the collector is \$ I_c = 9.8/10 k\Omega = 9.8 mA \$ and assuming \$ \beta = 100 \$ then \$I_b = 0.098 mA \$. But \$v_c = I_c \times R_c = 9.8\$ volts. For a transistor to be considered in the saturation mode \$v_c < v_b \$
My textbook has some contradictory statements about saturation mode. In the beginning of the course, we learned that when a transistor is in saturation mode, the collector should read close to zero volts. The book now says that when a HIGH (> 2 volts) is applied to the input supplied to the transistor's base, it will cause the transistor to conduct and the collector voltage drops to a LOW. But in the calculation from above (assuming that it was done correctly), I can clearly see that the voltage on the collector is 9.8 volts, close to 10 volts and not anywhere close to zero or LOW.
EDIT: Am I suppose to assume that \$v_c = v_{cc} - I_c \times R_c = 0.2\$. Since the emitter is grounded, \$v_c = v_{ce}\$