I've added a test inverting charge pump to an LMR64010 based boost regulator. This regulator outputs +12V (exact value is 11.88V) from a 7.4V battery pack.

This is a notated image from a Maxim application note showing what I did. The output capacitors are whatever I had handy - 22u and 10u in parallel:

enter image description here

With no attached loads I get a value for -V of -11.65V. The immediate issue I noted was with an attached negative load of 1K for approximately 12mA, the voltage immediately drops off to -6.5V.

Varying the load on the positive side (with a fixed negative load) I get:

Neg Load    Pos Load    Neg output (V)
   1k         inf          -6.50
   1k         3.3K         -9.95
   1k         1.0K        -10.30
   1k         500R        -10.38
   1k         250R        -10.40

So a rapid convergence to about -10.30 volts at a load that matched the negative load. Then little or no rate of return below that.

Is this a correct statement then: "an inverting charge pump must have a matching load on the boost converter output".

Is this how I should design the completed circuit (which is providing negative biasing for an opamp - not my design) ? So I'd put a 1K resistor across the +12V rail and then specify that loading (12mA or so) as a max loading for the negative rail?


2 Answers 2


Charge pumps driven from square waves have inherent apparent series resistance based on the frequency, and the size of the pump capacitor. You expect the output voltage to drop as it is loaded with decreasing resistance.

However, your table shows the opposite. Either you measured something wrong or wrote down the data wrong, or there is something else going on here. Keep in mind that in this case you have a feedback loop that adjusts the PWM duty cycle and possibly the period to keep the 11.9 V output regulated. This may be causing various non-obvious affects on the charge pump output. The pulses are there for another purpose and the charge pump is coming along for the ride.

This probably doesn't matter much if you only want a few mA, like the negative supply of a opamp. Make sure to filter this well before using it to power a opamp. I'd put a ferrite chip inductor followed by a 20 µF or so ceramic cap to ground before the opamp power pin at least, maybe two of those filters in series. The opamp will have some supply rejection capability, but that won't work well at high frequencies. You need to filter out enough of the high frequency noise from the charge pump supply so that the active circuit in the opamp can handle the rest.


You are now measuring the negative supply voltage with a fixed 1 kΩ load on it, while varying the load on the positive supply. The relationship you measured makes sense. By increasing the load on the positive supply, the feedback mechanism increases the duty cycle and/or frequency of the switching pulses. This lowers the effective resitance of the charge pump negative supply. This is all a consequence of the pulses being produced for the purpose of regulating the positive supply, which is not necessarily optimal for regulating the negative supply. The harder the switcher has to work to maintain the positive supply, the better job it does of driving the negative supply too.

  • \$\begingroup\$ Apologies for that - my data wasn't clear enough. I've edited the post. I was varying the load on the positive side only while holding the load on the negative side. I'm currently assuming that, if the negative is going to tag along for the ride, the positive needs at least the same output for whatever non-obvious reason. I'd considered raising both sides to +/-16V and using linear regs but I take your point about the inductor filter (Pi filter I guess). I'll absolutely do that... \$\endgroup\$
    – carveone
    Commented Dec 11, 2014 at 15:28
  • \$\begingroup\$ That makes perfect sense. There's no real way of magically telling the boost regulator to maintain the negative supply other than by maintaining the positive to at least the same extent. I've been told that I need to supply less than 5mA at -12V. So just sticking a 1k resistor across the positive supply should maintain the negative to that extent. There'll be a limit note on my schematic though! \$\endgroup\$
    – carveone
    Commented Dec 11, 2014 at 15:48

The 4u7 switching capacitor is partially in the regulation feedback loop. But it's effect is blocked by the +12V output diode if the +12V output capacitor does not drain at all when there is no +12V load. So it is not exactly "an inverting charge pump must have a matching load on the boost converter output", but it does need some minimum load at the primary output.

My guess is that with the 1K at the primary output, you can probably draw more than 12mA from the negative. Increasing the 4u7 capacitor should improve the regulation slightly.


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