2
\$\begingroup\$

The smartphone seems to have bq24190 chip for power and charging control (according to /sys/), for which the data sheet specifies that it can be powered not only from USB's 5V, but also from up to 18V.

Does it mean I can charge my Huawer Honor 6 directly from 12V? Where to find the absolute maximum ratings for a smartphone?

|improve this question
\$\endgroup\$
  • \$\begingroup\$ The reality is the manufacture is not going to tell you it can be charged from 12V, even if it won't hurt anything. They want all the sheeple using it to charge it from the supplied power brick. \$\endgroup\$ – Matt Young Dec 31 '14 at 14:48
  • \$\begingroup\$ How safe is to try to gradually increase input voltage while monitoring current to "probe" the actual maximum? For example, my previous smartphone just refused to start charging if input voltage is 6V. \$\endgroup\$ – Vi0 Dec 31 '14 at 14:51
  • \$\begingroup\$ Is it worth trying to send them a letter and ask directly? \$\endgroup\$ – Vi0 Dec 31 '14 at 14:52
  • \$\begingroup\$ What are you hoping to gain by charging from 12V? It's not going to be any faster. \$\endgroup\$ – Matt Young Dec 31 '14 at 14:52
  • \$\begingroup\$ @MattYoung, I can use DIY unregulated battery chargers more easily. For example, using stand-alone 12V car battery as super-power-bank. Why chain buck regulator with another buck regulator in the phone itself? \$\endgroup\$ – Vi0 Dec 31 '14 at 14:53
7
\$\begingroup\$

There is no such thing like "datasheet for phone".

Phone is consumer electronics. Consumer doesn't have to know all these things. All you can/should get from manufacturer is manual (that usually says: "use original battery charger").

I would not recommend trying to power phone from 12V even if you are sure that there is BQ24190 chip, because you don't know what else is there. Maybe some zener diode that will blow up without any other damage, maybe some extra ESD protection designed for 5V and you will destroy whole ESD circuitry).

|improve this answer
\$\endgroup\$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.