2
\$\begingroup\$

Like voltage shunt, voltage series, current shunt, current series. I can seperate them with opamps or box diagrams very well(its easy i guess) but when it comes to a point that we use real transistors and resistor and capacitors i cant understand which one is wich. I checked some books also the web and they all have something like boxes which the gain is written in them but i couldn't find a direct way to seperate negative feedback types with a given real transistor resistor capacitor circuit. I hope my question isn't silly.

circuit diagram for feedback

for example this circuit. what should i check first? then according to it what should i do next. and how to decide it is current series. if you can answer as it is an algorithm it would help me understand way better. Thank you in advance

\$\endgroup\$
  • \$\begingroup\$ Personally I don't understand your question. Perhaps you can clarify with some diagrams if nobody else provides a sufficient answer. \$\endgroup\$ – Brian J Hoskins Jan 10 '15 at 12:31
  • \$\begingroup\$ @BrianJHoskins i hope this way is more clearer for you and everyone else. Thank you for your attention in either way \$\endgroup\$ – Aykut Dos Jan 10 '15 at 13:04
  • \$\begingroup\$ As you can see, I have included this example in my detailed answer (current-controlled voltage feedback). \$\endgroup\$ – LvW Jan 10 '15 at 14:13
1
\$\begingroup\$

No - I don`t think that your question is "silly". It is, indeed, in some cases not easy to identify the type of feedback. At first, you have to find out which output quantity (current or voltage) determines the feedback signal. And secondly, it is important if this feedback signal is a current or a voltage.

In most cases, it is not a problem to answer the first question (output quantity). For answering the second question (feedback quantity) it is best to find out how the feedback signal is combined with the input signal. This can be best explained using an example (opamp with feedback):

1.) For the inverting opamp amplifier the input signal is combined with the feedback signal in a common node (directly at the inv. input terminal). In such a node only two CURRENTS can be superimposed. Hence, we have voltage-controlled current feedback. This case can be transferred to a BJT amplifier, which has a feedback resistor from the collector node to the base node. In this case, signal feedback is established because the input signal is connected via a series resistor to the base node.

2.) For a non-inverting opamp amplifier the input VOLTAGE is directly superimposed with the feeedback signal using the differential input of the opamp. Hence, the voltage difference directly results from the feedback voltage. In this case, we have voltage-controlled voltage feedback. A similar case exists for a BJT amplifier (common emitter configuration) which has an emitter resistor RE. Here, the driving voltage difference Vbe directly results from the difference input voltage minus feedback voltage (developed across RE).


In some cases, it might be helpful to look at the input resistance. In most cases, it is not a problem to see if the feedback path causes an increase or a decrease of the input impedance. In the first case (increase) we have voltage feedback and in the second case (decrease) we have current feedback.

\$\endgroup\$
  • \$\begingroup\$ Thank you sir! This clearifies most of my question but if there is one i need an answer like a algorithm, check this if this is like that than check this alike. but this helps also a lot so thank you. \$\endgroup\$ – Aykut Dos Jan 10 '15 at 12:59
  • \$\begingroup\$ i dont know why but it took more time to sink in for me but i get it now i'll mark this as an answer. \$\endgroup\$ – Aykut Dos Jan 10 '15 at 16:24

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.