Ignoring the voltage drop on the diodes, for a full wave rectified DC,can I say that:
1) Vrms of the original AC = Vrms of the rectified DC. ( I have just flipped one polarity. Power is same)
2) Vdc = V average = Vrms / 1.11072 ( the ratio between Vrms and V average)
( 0.7071 / 0.6366 = 1.11072)
(0.6366 / 0.7071 = 0.9003)
If I view the rectified DC as a mixture of pure DC, and AC component, the V average is the pure DC component.
3) Since I know the Vrms and the Vdc, can I calculate the AC component voltage this way:
The Vrms of the AC component would then be Vrms of the original AC sine wave / 0.435.
If this is all wrong, what is the correct ratio? I am looking for an answer without using functions. Should the AC component be referred to as Vrms or V effective or both are ok?