1
\$\begingroup\$

Does anyone know how to model a depletion mode N channel MOSFET in spice?

I have looked online however the majority of resources have shown how to model a depletion type or enhancement type. I specifically want to model a FET that is fully on when there is a 0 Vgs voltage.

Resources i've looked at

\$\endgroup\$
4
  • \$\begingroup\$ Can you explain the distinction you're making between "mode" and "type" in this context? \$\endgroup\$
    – Dave Tweed
    Jan 21, 2015 at 19:06
  • \$\begingroup\$ @DaveTweed In this context I am looking to model a fet where when Vgs is 0, current will flow freely between the drain and source. When Vgs > Vth the channel will close an only leakage will flow. Does that explain? \$\endgroup\$ Jan 21, 2015 at 19:14
  • \$\begingroup\$ Can you give a link to the material you found about depletion "type" MOSFETs? \$\endgroup\$
    – The Photon
    Jan 21, 2015 at 19:17
  • \$\begingroup\$ @ThePhoton the second one mentions depletion mode devices be I believe it's just referring to p channel fets. Also please tell me if there's a better nomenclature for these parts / behaviors \$\endgroup\$ Jan 21, 2015 at 19:24

1 Answer 1

4
\$\begingroup\$

The solution is given in the LTSpice help file you linked:

VTO is positive (negative) for enhancement mode and negative (positive) for depletion mode N-channel (P-channel) devices.

For an NMOS FET, if VTO is positive, you have an enhancement mode device. If VTO is negative, then you have a depletion mode device.

For a depletion mode NMOS FET, with 0 Vgs the channel will conduct. Vgs must be pulled below 0 V in order to cut off the channel. In SPICE this behavior is represented by a negative threshold voltage, controlled by the VTO parameter.

From your comments, though, you want

When Vgs > Vth the channel will close an only leakage will flow.

To get this behavior, you need a p-channel depletion mode MOSFET. An n-channel FET doesn't work this way.

\$\endgroup\$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge that you have read and understand our privacy policy and code of conduct.

Not the answer you're looking for? Browse other questions tagged or ask your own question.