I designed a simple half bridge circuit using popular FET driver IR2101 (switching freq. around 500 Hz, drain current about 250 mA, supply voltage about 12 V):

Schematic of the half bridge

Of course I have resistive load connected between the VS node and ground, forgot to draw it.

This is a part of a bigger schematic, but the bridge circuit doesn't work as I expected. When the high side FET is on, the voltage drop across it (drain-source voltage) is about 2.1 V. When the low side FET is ON, everything is OK - the Vds voltage of it is around 0 V.

Voltage between LO and GND looks pretty good - a square wave from 0 to 12 V. Voltage between HO and VS looks exactly like this:

VGS of the high side FET

I guess that the problem is caused by improper driving the high side, ie. the bootstrap circuit. The gate voltage drops and the high side FET works in its linear region. What could I do to force it to saturate? Is the 1k G-S resistor a problem? I read that there should be such resistor to prevent FETs from various failure types.

  • 3
    \$\begingroup\$ Are you sure the 47uF capacitor is in place? That time constant looks more like the 330nF capacitor alone (with the 100 ohm in series with 1K ohm to discharge the cap). \$\endgroup\$
    – Tut
    Feb 16, 2015 at 15:56
  • \$\begingroup\$ May I ask why you have two capacitors hooked up in parallel between Vb and Vs? I am building using a gate driver to drive the FETs of my synchronous buck converter, and I am having similar trouble turning on the high-side FET. May I also ask how you calculated your capacitor values? \$\endgroup\$
    – L_t130
    Nov 10, 2015 at 21:52

2 Answers 2


Yes, the 1K gate-to-source resistor is creating your problem. The good news is, you don't need it. A gate-to-source resistor is needed if your MOSFET cannot be actively driven off when it is needed to be, but that is not the case with the IR2101. You will often see a gate-to-source resistor used when a MOSFET gate is connected to a microcontroller to force the MOSFET off until the microcontroller can initialize the pin as an output.

Here is the datasheet for IR2101. And here is the Functional Block Diagram (from the datasheet):

IR2101 Functional Block Diagram

As you can see from the functional block diagram, the gate drive outputs HO and LO are actively driven both high and low so the 1K ohm resistor is not needed.

The problem that you are seeing is that the bootstrap capacitor is being discharged through the 1K ohm resistor (in series with the 100 ohm resistor). From looking at the decay rate on your waveform, it looks as though that waveform was captured with only the 330nF capacitor in place (using the formula T=RC to get the time-constant).


You were right guys, the technician I asked to build a prototype of this circuit soldered the positive electrode of the 47 uF cap to the gate of the FET, between resistors, instead of connecting it to VB. Doh! I haven't checked that out assuming he did it right. Now everything seems to be fine. And yeah, I'm using pretty long deadtime, around 1 us. Thanks a lot for help!


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