# Why does a large filter capacitor draw large (peak) current?

In my book it says that in a diode rectifier the capacitor gets charged close to the peak of the ac voltage.

1. Is it true the larger the (filter) capacitor the larger the peak current drawn and if so why?

2. And why is it that when the capacitor gets charged to a value close to the peak of the ac (input) voltage that the current through the rectifier is very large near the peak of the 50-Hz ac (input) voltage ?

$$i = C \frac{dV}{dt}$$