3
\$\begingroup\$

Problem given by my Prof

I was given this problem by my prof and his answer is simply that it is a parallel RLC circuit and he uses $$s^2 +\frac{1}{RC}s+\frac{1}{LC} = 0$$ for the characteristic equation. It seems to me that it is invalid and when I try to find the solution using differential equations and either nodal analysis or mesh I can't seem to arrive at this solution.

Am I wrong on this "standard" characteristic equation is only valid for a circuit where the three elements are parallel and in this case the inductor and resistor are in series and thus it cannot be used?

\$\endgroup\$
1
  • \$\begingroup\$ You are right - the given equation does NOT apply. The midterm is s(R/L) \$\endgroup\$
    – LvW
    Feb 18, 2015 at 10:43

1 Answer 1

1
\$\begingroup\$

I have a little different opinion from your prof. The characteristic equation of an RLC circuit will be either of the two given below. $$s^2 + \frac{R}{L}s +\frac{1}{LC} = 0\tag1$$ $$s^2 + \frac{1}{RC}s +\frac{1}{LC} = 0\tag2$$

Reason:
The characteristic equation of a second order system is $$s^2 + 2\alpha s + w_0^2 = 0$$

Where \$\alpha\$ is a damping related parameter and \$w_0\$ is the natural undamped frequency.

For an RLC circuit, \$w_0\$ will depend only on L and C and it will be \$\frac{1}{\sqrt{LC}}\$.

Coming to the dimension of the characteristic equation, each term in it should have a dimension of \$\mathrm{radian^2}\$. So \$2\alpha\$ must have dimension of \$\mathrm{radian}\$. The only possible options are \$\frac{1}{RC} \$ and \$\frac{R}{L}\$.

Which equation applies where?

Equation (1) applies to RLC circuits in which two more components are in series. The two possible connection are:

schematic

The R L and C can take any of these positions Z1, Z2 and Z3, but only one position at a time.

Equation (2) applies to RLC circuits in which two more components are in parallel. The two possible connection are:

schematic

The verification of this result is left to the reader. :-)

In the circuit given in the question, two components R and L are in series and hence the corresponding characteristic equation will be (1).

\$\endgroup\$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge that you have read and understand our privacy policy and code of conduct.

Not the answer you're looking for? Browse other questions tagged or ask your own question.