# discharge of capacitor through a current source

Assume we have a cap connected to a current source that draws a current $I_0$. What time would it take to discharge the cap by a voltage $V_t$?

$$t=\frac{C \times V_t}{I_0}$$

Is this correct or am I wrong?

• Yes, Q = It = CV; so t = C*V/I. – Circuit fantasist Feb 20 '15 at 20:33

This is correct. The charge of the capacitor is given by: $$Q=CV$$ and for constant current $I$, the charge is $$Q=I\cdot t$$ So $$CV=I\cdot t$$ which leads to $$t=\frac{CV}{I}$$