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I am currently making some calculations and also simulations on a PT100 circuit, the circuit itself and calculations are not an issue, but I am trying to look at the best rail to rail opamp. An image of the circuit is below:

enter image description here

Currently the university were I am studying has TLV272 and I intend to build a prototype for calibration and testing, with tweaked values pending what 1% resistors we have.

What I am interested in is the benefits of using an OPA188 opamp as opposed to the TLV272, I don't have a Pspice model for the OPA188 so cannot check. I know the OPA188 is stated as low noise, I don't believe parameters which are speed related are an issue here as it's a low speed signal conditioning circuit. Input current yes so Iq per channel, not sure the significance of IIB as the value seems counter intuitive to me and not sure I fully understand the implications of a large or small value here?

OPA188

TLV272

Any further advise would be welcome, I am also thinking of adding a small pre-amp stage to boost the range of the output, then add this circuit afterwards as have 2 Opamps per package.

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  • \$\begingroup\$ Please describe the nature of your inputs and output. Hard to talk about rail to rail performance without understanding why you need rail to rail. \$\endgroup\$ Commented Feb 24, 2015 at 12:22
  • \$\begingroup\$ Just as a matter of convention GND is drawn lower on the page than VDD or positive Voltage sources to aid understanding where possible. \$\endgroup\$
    – Spoon
    Commented Feb 24, 2015 at 12:54
  • \$\begingroup\$ @ScottSeidman fair comment and tried to keep it short. Ok I am using 2 arduinos as a datalogger with 7 PT100 sensors, this will eventually be a completely battery operated system running off a small solar cell (10W) and battery. I have also mainly used rail to rail in the past. Output will be 5V to the ADC, I will also use a stable 5V reference for the PT100 node voltage. \$\endgroup\$
    – Ant
    Commented Feb 24, 2015 at 13:07
  • \$\begingroup\$ @Spoon Yep understand and agree it looks a little confusing \$\endgroup\$
    – Ant
    Commented Feb 24, 2015 at 13:08
  • \$\begingroup\$ So why the differential input for a simple RTD?? If you have two op amps to throw at it, thats not the circuit I'd be using \$\endgroup\$ Commented Feb 24, 2015 at 13:38

2 Answers 2

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Input bias current is the current that potentially comes out of your input pins, and its impact may be multiplied by your gain, depending on your configuration. Add a current source at each input corresponding to the bias current, and figure out if the resulting offset is important to you. Do this for the MAX values, and ignore the min.

Take your input noise density, and multiply by the gain and bandwidth to figure out what your output will look like.

It looks like the TLV272 wins for bias currents (maybe a factor of 3), and loses for noise (order of magnitude).

For temp measurement, you can reduce your bandwidth to get rid of the effects of noise, but dealing with offsets can be more troublesome

ADDITION: Some of the discussion leads me to point out that when doing design like this, an engineer would generate an ERROR BUDGET and then figure out how to reach it. In this case, I'd probably start with quantization noise, and figure out if I need my output to be full scale-- i.e., do I need a rail-to-rail output in the first place? Then I'd factor in noise, nonlinearity over the scale of interest, and the effects of bias current. If bias current turns out to be a big consideration, but quantization noise doesn't, I'd be inclined to opt for a non rail-to-rail op amp, but with low bias and noise, and avoid the design tradeoffs needed for design of rail-to-rail amps.

It's tempting to design to the strategy that EVERYTHING should be built as accurately and precisely as possible, but its an incredible waste of resources. The best engineers figure out what the specifications need to be, and build to them. If you see an engineer or an engineering team that consistently EXCEEDS specs, then you're looking at a waste of resources.

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  • \$\begingroup\$ Thanks, so would I be correct in saying smaller bias currents are better as loads the input circuitry less? I think I assumed the OPA188 was better on all parameters which confused me when reading the IIB value, but there are trade-offs I guess by improving one parameter it suffers in others. \$\endgroup\$
    – Ant
    Commented Feb 24, 2015 at 14:07
  • \$\begingroup\$ For bias and offset currents, smaller is desirable, but probably not necessary for this application. \$\endgroup\$ Commented Feb 24, 2015 at 14:16
  • \$\begingroup\$ @ScottSeidman - For mass-produced items, I'd agree with your statement about exceeding specs. However, I'm from an R&D aerospace environment, and I can testify that overdesigning and overbuilding flight articles has saved our sorry behinds more than once. \$\endgroup\$ Commented Feb 24, 2015 at 14:22
  • \$\begingroup\$ @WhatRoughBeast, aerospace is sick specs and zero failure tolerance, with (comparatively) sick budgets and timelines to match! Read some incredible stuff on zero-bug programming, too! \$\endgroup\$ Commented Feb 24, 2015 at 15:32
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By IIB I assume you mean the input bias current. An ideal op amp has infinite input impedance, which means that no current is drawn or sourced by the inputs. Real op amps, of course, are not ideal, and the input bias current is simply the amount of current flowing into or out of each input during operation. Equally important is the input offset current, which is simply the difference between the two.

Bias and offset currents are (or can be) important, because they flow through the resistors connected to each input, and the combined iR drop constitutes an error voltage. For the configuration you show, the voltage error at each input due to bias currents is just the parallel equivalent of the 3 resistors. In each case, one of the 3 (R4 and PT) is much smaller than the others, so the others can safely be ignored for a quick analysis.

If the two dominant resistors were equal, the effective error voltage would just be the resistance times the offset current. Since R4 is 10 times PT, the number to consider is the bias current times R4.

In this case, the OPA188 has a worst-case (at 125C) bias current of 8 nA, compared to 1 nA for the TLV272 over the same temperature range. You should check the bias specifications for yourself, and determine which temperature range you need to worry about, since for lower temperature swings the bias currents go way down. So in this case the TLV272 is better.

Is the difference significant? The worst-case bias current error for the OAP188 is 8 nA time 1k, or 8 uV. A one-degree rise on the pT100 will give a resistance change of ~0.4 ohms, or about 42 uV, so the bias error is the equivalent of about 0.2 degrees.

I don't know what your system requirements are, but I suspect that either op amp will do just fine.

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  • \$\begingroup\$ thanks you for this good information and torn between which reply to mark as answered my question and both answers have helped me understand the problem better. \$\endgroup\$
    – Ant
    Commented Feb 24, 2015 at 14:11
  • \$\begingroup\$ @Ant I just realized that my equivalent voltage calculation was off. The temperature equivalent error is 0.2 degrees for this worst-case temperature range. I've edited my answer to show this. Sorry. \$\endgroup\$ Commented Feb 24, 2015 at 14:15
  • \$\begingroup\$ no problem its good to see the reasoning behind it and really appreciate you taking the time to answer. \$\endgroup\$
    – Ant
    Commented Feb 24, 2015 at 14:19

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