I have the TL071CP op-amp, and I am trying to make a simple DC voltage follower, however, I only get a couple hundred milivolts at the output. Usually 200-450mV. Any idea why?


simulate this circuit – Schematic created using CircuitLab

  • 2
    \$\begingroup\$ This opamp chip is expecting a bipolar supply and you are giving it a single supply rail. This changes the operation of the chip. \$\endgroup\$
    – user39962
    Mar 6, 2015 at 17:23
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    \$\begingroup\$ Yeah, it's absolutely the wrong choice of op-amp for a simple voltage buffer using single supply. \$\endgroup\$
    – KyranF
    Mar 6, 2015 at 17:25

1 Answer 1


To expand on the comments a little: A TL071 is the wrong opamp for the configuration you're using, because you've exceeded the "Common-Mode Input Voltage Range" spec.

If you go to Table 6.3 on page 6 of the datasheet and look for the Vicr (Common-mode input voltage range) line you'll see that with a +15V/-15V supply (that's 30v from + to -), the minimum guaranteed input voltage range is +-11V. That's 4V away from each supply.

So, with your single 9V supply and the same rule applying, your input voltage must lie in the range of 4 to 5V in order for the opamp to behave properly. The 2.5V from your voltage divider is clearly out of range.

Even if you look at the more lenient data from the 'Typical' column, the range is -12 to +15 with +15/-15V supplies and this would lead to an input range of 3V to 9V with your single 9V supply. So your 2.5V input is still out of range.

Try to find an opamp which is intended to run from a single-supply (like an LM358) and you should see much better results.

  • \$\begingroup\$ I didn't really know that op-amps have this kind of limitation. Up till now I had the luck to work with op-amps that didn't have this limitation, so I just didn't know about such a thing. Thank you! :) \$\endgroup\$
    – Calin
    Mar 6, 2015 at 18:53

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