If a battery of 60v with internal resistnace 4kohm (in series) is connected to a zener diode of v_z=10v in parallel and a load resistance of 2kohm in parallel too, what will be the currents in different circuits. since zener diode will breakdown at 10 v the load voltage will be max 10 v so as 60 v is > 10 v the currrent in load must be 5ma and the remaining 50 v will be across internal resis. so the current in that branch will be 12.5 ma and using kirchoff's rule the remaining current must be 7.5. but this is wrong. I don't understand why. this is surely due to conceptual mistake.