# What's the difference between a 74LS05 hex inverter and a 74LS04 hex inverter?

It looks like the 74LS05 has "open collector outputs" (not sure what that is) and the 04 does not.

Plus, it appears the 05 is more expensive?

Can someone tell me the difference between the two and when would you use one vs. the other?

Thanks.

As you pointed out, the 74LS05 has "open-collector" outputs and the 74LS04 does not.

There are two general types of outputs in digital circuitry: push-pull and open-collector (OC). The latter name dates back to when BJT (bipolar junction transistors) were used in the output stage, for example TTL logic like the LS series; you will also see the nomenclature open-drain (OD) output, to reflect CMOS topology.

Push-pull outputs, which are in the 74LS04 drive the output high (to the level of the power input of the chip, typically 5v or 3.3v) to reflect a logic 1 (this is called "sourcing"). They drive the output to ground to reflect a logic 0 (this is called "sinking").

Open collector / open drain outputs which are in the 74LS05 also drive the output to ground for a logic 0, but for a logic 1, they leave the output in an high impedance state -- as if the pin was disconnected from the chip.

What good is that? Well it allows the output of several chips to be tied together, and they won't be interfering with each other all trying to drive the line high. One example is several devices with interrupt outputs feeding into a single interrupt pin on a microcontroller. When there is no interrupt, the line is high. How, if no output is driving it high? Somewhere there will be a "pull-up resistor" (common values are 4.7K or 10K for TTL, and higher values for CMOS) tied to system power (again typically 5v or 3.3v) to pull the line to the logic 1 level as a default.

Then when an interrupt occurs, the chip causing the interrupt will pull the line to ground. Since the pull-up resistor is a fairly high value, this will not draw very much current, about 1 mA for a 4.7 K resistor and 5V logic. The line into the microcontroller going to a logic 0 will be recognized as an interrupt -- since this is caused by the line going from high to low, this is called an "active low" signal.

So open-collector/open-drain outputs are generally used when more than one output are tied together and driving one or more inputs, although it usually just one. Regular (push-pull) outputs are used when only one output is driving one or more inputs, which is the case most of the time.

This tying of several open-collector/open-drain lines together is the same as ORing them (except technically it would be done with a NOR gate with inverted inputs, which, remarkably, is the same as an AND gate) since the lines are active low. But this way you don't need to actually include the physical gate.

The 74LS05 is probably more expensive because there is much less demand for the chip. 74LS04 hex inverters are very common and sold in much higher volume.

• Excellent explanation for how OC works. One other way to look at it: if you are using several OC outputs tied together, basically you are building an "OR" gate, without requiring additional chips. – Kevin Keane Mar 14 '15 at 12:27
• @KevinKeane Good point - I'll add that to my answer. – tcrosley Mar 14 '15 at 12:33
• If I recall correctly, (at least some) open collector outputs can accept higher voltages than 5. You can use them to turn a 12V light on and off by connecting the light between 12V and the output. – Ross Millikan Mar 14 '15 at 15:14