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I want to model the transfer function of a resistor mathematically, and am after some resources / tips on if it's possible to do so.

For example, if I put 1V into a 1 Ohm resistor, I want to know how long and how (shape) it will take to reach a steady state temperature, given 25 deg C ambient.

I.e.

$$ \frac{T(s)}{V(s)} = ??? $$

Where T(s) is the laplace transform of temperature T(t), measured in say Kelvin.

I understand there are a lot of factors which will affect this model (material, size, shape, ambient (?)), but I'm not sure where to even start. A datasheet shows the heat rise at a certain load, but not really how it gets there. I can't find a time-domain function for the temperature rise either.

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  • \$\begingroup\$ I can't give you an answer, but there is some discussion of self-heating effects in this paper which may be useful (specifically page 3). \$\endgroup\$ – Roger Rowland Mar 22 '15 at 8:50
  • \$\begingroup\$ As with charging a capacitor, it will never really reach a stable situation, but over time it will approach it asymptotically. And the function of temperature over time will be different for various parts (inner versus outer) of the resistor. And the there is the influence of temperature on resistance... \$\endgroup\$ – Wouter van Ooijen Mar 22 '15 at 9:20
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There is not much EE in this question, but here is a simple model that can be a starting point. There are many simplifying assumptions, such as constant thermal conductance, constant heat capacity, uniform temperature...

Power_store_heat_capacity + Power_out_thermal = Power_in_electrical

$$ MC_p \frac{dT}{dt} + K_tT = \frac{V^2}{R} $$

T = temperature offset from ambient (K)
M = mass of resistor (Kg)
\$C_p\$ = heat capacity (Joule/(Kg*K)) = ~800 for some ceramics
\$K_t = \frac{1}{R_{th}}\$ = thermal conductance (Watt/K) = 1/(thermal resistance)

So there is no transfer function for T/V because the V-square term is non-linear.

Rewrite:
$$ MC_p \frac{dT}{dt} + K_tT = P $$
Laplace transform:
$$ MC_pT(s)s + K_tT(s) = P(s) => \frac{T(s)}{P(s)} = \frac{1}{MC_ps + K_t} $$

If you look in the datasheet that you linked, on the Heat Rise Chart, the thermal resistance is proportion to the slope. So it is clear that the thermal resistance is not constant as assumed by the above model. But for example, fit the 5W resistor curve to a straight line, there it gives a Kt (thermal conductance) estimate of 5W/75C = 0.066 W/K.

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  • \$\begingroup\$ Thank you so much. Do you happen to have a source for where you got your first equation (or the MCp * dT/dt part, if it's just the conservation of energy) from? \$\endgroup\$ – tgun926 Mar 23 '15 at 2:19
  • \$\begingroup\$ It is just from conservation of energy. I didn't get that from a particular source. \$\endgroup\$ – rioraxe Mar 23 '15 at 2:56

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