If assumption is that the meter has a 1 mega ohm resistance then the total resistance between ground and the 82K resistor is: 1,820,000 ohms. The current would not include the 18K ohm resistor in this case, therefore the total current would be: 4.65 volts / 1,820,000 ohms = 2.555 micro Amps The voltage drop across the 82K ohm resistor would be: 2.555 micro Amps X 820,000 ohms = 2.095 Volts. The voltage drop across the internal 1 mega ohm resistor of the meter would be: 2.555 micro amps X 1,000,000 = 2.555 volts. Total Voltage: 2.095 + 2.555 = 4.65 Volts.
If you take the voltage measurement from C to D (C to ground) it now includes both resistors and the 1 mega ohm resistor of the meter to get total resistance. Divide total voltage by total resistance to get the total current and use that to compute the voltage across each resistor. This is all based on the meter resistance included in the circuit. Otherwise everywhere in the circuit is just an open circuit with 4.65 Volts when the meter is not included in the circuit since open circuit equals 0 current (amps).