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at no load my boost converter, will be the same as in the photo. I'm thinking without a load at the end of the boost circuit the output impedance will be very high which will make the potential difference after connecting the output to a (semikron an-8005) which has an input impedance of 30k will make the boost output decrease to around 70v and if I take the output of the semikron inverter to a filter and then 1K load after that the voltage will decrease even more to around 6V only!

how can I avoid this drop, is putting a very high resistor in parallel with the output capacitor of the boost will solve this drop?

thanks and regards

enter image description here

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You should consider dynamically adjusting the mark-space ratio to keep the output voltage level fairly constant across a wide range of loads. The picture below should give you an idea: -

http://www.dos4ever.com/flyback/boost2.gif

Is putting a very high resistor in parallel with the output capacitor of the boost will solve this drop?

No, this will have no beneficial effect at all.

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