1
\$\begingroup\$

Here is how the circuet looks.

Initally the output the D flip flop is HIGH, when the there is HIGH to LOW input across the multivirator, it create a pulse of 200ms, which is connected to the Clear pin of the Flip Flop.

Shouldn't this happen?

  1. Q outputs Low
  2. Causes U5A to output HIGH
  3. Which in turn causes the Flip-Flop Set to HIGH
  4. Q outputs HIGH
  5. Causes U5A to output LOW
  6. Due to reset still HIGH causing Q to output Low
  7. Cycle Repeats

But this does not happen, can anybody explain why?

Is it due to propagation delay time of each device?

Propagation of Flip flop is around 150ns whereas of NAND is 200ns, there are actually 4 more NAND (not shown connected as not gates).

enter image description here

\$\endgroup\$
  • \$\begingroup\$ In your simulation you may want to add a pull down resistor from the junction between the cathodes of D1 and D2 to ground. Otherwise the pin of U2A (can't read what it is from your image as it is too small) will never be pulled down to zero. \$\endgroup\$ – Tom Carpenter Apr 25 '15 at 6:15
  • \$\begingroup\$ Yes I missed it, but the problem still exists. The circuit is actually in use and behaves similarly.BTW for the U2 minimum pulse width of set or reset is around 100ns. which is well under the PD after the NAND gates \$\endgroup\$ – Karthik Shetty Apr 25 '15 at 6:20
  • \$\begingroup\$ "But this does not happen, can anybody explain why" -- what does happen? \$\endgroup\$ – tcrosley Apr 25 '15 at 9:12
  • \$\begingroup\$ Well I think it should oscilate at a very high frequency... But in reality there is no change in output \$\endgroup\$ – Karthik Shetty Apr 25 '15 at 9:36
1
\$\begingroup\$

I suspect that you are getting burned by mixing CMOS and TTL. The output of a 74ALS00 is only guaranteed to produce a HIGH voltage of 3 volts. Add in a diode drop of 0.7 volts, and in theory the input to the 4013 could be as low as 2.3 volts. Since the minimum input high voltage for a 4013 at 5 volts is 3.5 volts, this would produce the failure to oscillate that you're seeing. As a matter of fact, the minimum high output voltage you need from the 74AL00 is ~4.2 volts, and that is not obviously in the cards.

What you should do is replace the last inverter in your delay chain with a CMOS chip, and put a 1k pullup resistor on its input. Failing that, simply putting a 1k pullup resistor on the output of the last delay inverter may (possibly) solve your problem. Also, make sure the pulldown resistor at the diode cathodes is large, something like 10k.

\$\endgroup\$
  • \$\begingroup\$ In actual the used NAND gate is 4093, with a pull down resistor across SET. I just want to know whether the O/P Q oscillates or changes state or is does not change? p.s. in the actual ckt it just changes state \$\endgroup\$ – Karthik Shetty Apr 29 '15 at 8:48
  • \$\begingroup\$ Try this. Get rid of S2, D1, D2, and the pulldown resistor, and connect the last NAND directly to the SET input. See what happens. \$\endgroup\$ – WhatRoughBeast Apr 29 '15 at 13:43

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.