I have 70Vrms sine wave, I rectified it with full wave rectifier. So the output is 100Vp.
I will divide it down to 1V using voltage divider (0-100V to 0-1V). How could I add a 1.4V DC bias to the output of the voltage divided ?

Briefly: $$ 70V_\text{rms} \Longrightarrow 0-100V_\text{p} \Longrightarrow 0-1V \Longrightarrow 1.4-2.4V$$

  • I have a 5V DC I could used it in the biasing

Spehro Pefhany, it is hard to find exactly this resistors values:

I read in another answer (Note also that this circuit does not isolate V1 and V2 from each other as a summing inverting amplifier would. Each sees the other with a impedance of R1+R2. Maybe that doesn't matter, but you need to at least think about it.(

Will this circuit work? schematic

Mr. Spehro Pefhany, I had a lot of distortion in my signal after I did the voltage divider as us advise my to do it.

Here is my project enter image description here

When the voltage is 56Vrms, I get the following results ( the green is the signal at PWM pin1 and the yellow is at R6 -the AM demodulator- ) enter image description here

The voltage at pin 1 of the PWM IC (UC3526AN) have to be 1.4VDC bias with 1Vpp when te input voltage is 100Vpp but it is not. The following is the real measurements at pin 1.

  • At about 20Vrms input enter image description here
  • At about 30Vrms input enter image description here
  • At about 68Vrms input enter image description here
  • At about 100Vrms input enter image description here
  • \$\begingroup\$ Is this a signal voltage or power? \$\endgroup\$ – Dzarda Apr 25 '15 at 17:50
  • \$\begingroup\$ it is to measure the voltage output of a unit under test ( he full load current is 2A \$\endgroup\$ – John Alawi Apr 25 '15 at 18:34

You can just use an op-amp adder, or just a voltage divider if you can live with higher output impedance and low input impedance.

For example (voltage divider):


simulate this circuit – Schematic created using CircuitLab

R1 is picked arbitrarily, and the remaining two values are chosen so that R2||R3 = 2.02K (so the output voltage changes 1.00V for a 100V change in the input) and 5V * (R1||R2/(R3+R1||R2) = 1.40V

Output impedance is R1||R2||R3 = 2.0K

Edit: Depending on the accuracy you need (which you did not state) you can use the closest E96 values of 1% resistors (eg. 7.15K, 2.80K) which would give you a gain of 100:0.996 and a bias of 1.393V (nominally). For a higher accuracy divider you could use available 0.1% resistors and combine them with 1% resistors to get very close to the desired values (or simply use something close and adjust the result digitally).

  • \$\begingroup\$ if R2=2.7k and R3=6.8 the ration will be 100:0.996 and DC bias is 1.407V. thinks very much for the help \$\endgroup\$ – John Alawi Apr 25 '15 at 21:24
  • \$\begingroup\$ @Yusuf 0.957 and 1.407V \$\endgroup\$ – Spehro Pefhany Apr 25 '15 at 22:31

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