# What did common mode input voltage do for a fully differential opamp?

I just want to know, what does the common mode input voltage in a fully differential op -amp do?

e.g. for a Op-amp,

$$V_1 = \dfrac{V_1 + V_2}{2} + \dfrac{V_1 - V_2}{2}$$

$$V_2 = \dfrac{V_1 + V_2}{2} + \dfrac{-(V_1 - V_2)}{2}$$

thus, $\dfrac{V_1 + V_2}{2}$ is the common part and $\dfrac{V_1 - V_2}{2}$ is the differential part of the signal.

There are three inputs, two are the differential voltage inputs. One is the common mode voltage input. I do not know what this pin means? Is it supply an offset?

for the Op Amp that i use is available under the link THS4524

• Which opamp are you using? Commented May 11, 2015 at 12:18
• Op amps typically DON'T have a common mode input. Please attach part numbers and circuit diagrams, so we know what you're talking about Commented May 11, 2015 at 12:44
• i haved posted the op amp that i used. Commented May 11, 2015 at 13:59
• This part is not an operational amplifier. Commented May 11, 2015 at 19:12

It's an output common-mode voltage, not input. So, the output is differential around whatever voltage you apply to the common-mode pin (assuming you have enough headroom for it to still act like an opamp).

• hi, thank you for your commemts. sorry, but i have posted the datasheet, it says it is Common mode voltage input。。。 Commented May 11, 2015 at 16:34
• sorry, but you don't understand the datasheet. It is an input to the CHIP not an input to the amplifier. Can you read a schematic? Look at the functional block diagram of the chip you linked to. You'll see that the common-mode input pin is used in a negative feedback loop to drive the common-mode (average) OUTPUT of the amplifier to the voltage you supply to the common-mode input pin. This is pretty standard for a differential amplifier. Commented May 11, 2015 at 16:57

If you go to the online datasheet and scroll to the Typical Applications page, you'll see

Figure 79 shows the modifications made to the circuit. Note the resistor connecting the VOCM input of the THS4521 to the input common-mode drive from the PCM4204 is shown removed and is optional; no performance change was noted with it connected or removed.'

Also if you look at the Electrical Specifications, you will see that all the specs are measured with 'VOCM = Open'. So don't worry about it.

Like the other answer mentions it is an output voltage.

It's an input with a twist. Look at this diagram - an amplifier (OPA2350) is feeding the "input": -