Previous answer is correct. However, there may be a solution to this.
Your V+ is connected to +15V. Your V- is connected to 0V. Hence your output voltage swing can't go as low as 0V. If you apply a negative voltage to V- (pin 8) of -3V or below, then you should be able to get your output voltage to drop down to 0 volts. You can do this with a couple of resistors acting as a potential divider. Use two reistors in series.
---V15V -> ..pin 8.. V+ of LM1458
|------- > OV point (GND)
----- V0V -> ..pin 4... V- of LM1458
Make R a fairly large value so you're not draining too much current from the supply.
Make the 100K resistor connect to the GND in the diagram above.
The opamp is still being fed with a difference of 15V between V+ and V-, but V0V is now 7.5 voltages below GND.
Something like this ought to work. I did something similar with a 741 op amp configured as a wien bridge oscillator fed from a 9 volt battery. The key is recognising that the battery is 9 volts potential difference between the terminals, but you can share that 9 volts across two equal sized resistors to give 4.5volts difference across each. And then make your centre point of the resistors your 0V (a 0V common). Voltages are relative, they're all differences between two points.