1
\$\begingroup\$

I am using a 4N25 opto-coupler for 5kHz to 10kHz application. In some datasheets the turn on and turn off times are mentioned to be 3us. I am wondering if this opto-coupler is suitable for my circuit's frequency. Doesn't it much distort the output which is supposed to turn on gate of a power Mosfet?

In a SE question, in the accepted answer, it is mentioned that connecting base to emitter via a resistor such as 220k or 470k can increase speed of switching. Does it mean that t_on and t_off decrease by connection via R_BE ? and how much can I expect to improve speed by that?

\$\endgroup\$
  • \$\begingroup\$ Kelvin-Hertz is not a unit of anything meaningful to this question. \$\endgroup\$ – Olin Lathrop May 14 '15 at 11:55
  • \$\begingroup\$ @OlinLathrop Where is Kelvin-Hertz proposed? \$\endgroup\$ – zahmati May 14 '15 at 11:58
  • \$\begingroup\$ In the first sentence of your question - twice. Also, specifying resistors in units of degrees Kelvin makes no sense either. \$\endgroup\$ – Olin Lathrop May 14 '15 at 12:00
  • \$\begingroup\$ @OlinLathrop So how do you show Kilo Hertz? \$\endgroup\$ – zahmati May 14 '15 at 12:03
  • 3
    \$\begingroup\$ @OlinLathrop I agree that this is getting silly. It was clearly a mistake, and the units were obvious, whether its KHZ, KHz or kHz. Correct the units, and move on, why berate him on units unless the understanding of the units was unclear, such a 5kF resistor. \$\endgroup\$ – efox29 May 14 '15 at 13:17
4
\$\begingroup\$

No it's rather unsuitable. The 2us given on the datasheet is with a load of 100\$\Omega\$- which is a totally unrealistic load when used in a simple circuit.

If you allow a CTR of 10% (half the minimum when brand new) and put 10mA through the LED, you'll have 1mA at the phototransistor. A load of 10K would be reasonable, so delays will be in the tens of microseconds. See this datasheet.

enter image description here

It's not quite as bad as being proportional to the load resistance, but well in that direction, so the 100 ohms condition on the datasheet could, at best, lead to a bad conclusion. You could put a complex circuit around the phototransistor and get down to the datasheet numbers (which are not ouright lies, just misleading) and the base resistor you suggest will further reduce the numbers somewhat (at the expense of CTR, so a simple circuit does not benefit).

I suggest you use a logic-output optoisolator such as the 6N137 or similar. They use a photodiode internally with a sensitive and fast circuit, which is a much more suitable method for high speed. Optoisolators with phototransistor (or photodarlington) output generally should be avoided where speed is of much importance.

\$\endgroup\$
  • \$\begingroup\$ So what opto-coupler do you think is suitable for this range of frequency? Any suggestion? \$\endgroup\$ – zahmati May 14 '15 at 11:59
  • \$\begingroup\$ @zahmati See above- it's easy to get guaranteed delays in the 100ns range, which should be quite acceptable unless you use a bad circuit where propagation delay has an effect on dead time (thus potentially causing shoot through in a bridge or half-bridge). \$\endgroup\$ – Spehro Pefhany May 14 '15 at 12:08
  • \$\begingroup\$ Thank you it helped much. Since I am using opto-couplers to turn on gate of Power Mosfet, does it mean that my R_L is very high which includes resistance of gate paralleled with a 10K resistor as pull down? Logic gate transistors seem to be good idea however I have 4 floating transistor with 8V voltage on them. which make usage of logic gate hard in this case. \$\endgroup\$ – zahmati May 14 '15 at 12:21
  • \$\begingroup\$ You need a MOSFET gate driver plus the optoisolator. If supplies are required- create them. This is outside the scope of the original question. \$\endgroup\$ – Spehro Pefhany May 14 '15 at 12:26
2
\$\begingroup\$

Your first question can be directly answered from the numbers you have provided. The fastest speed you want to pass is apparently 10 kHz, which has a period of 100 µs, and level times of 50 µs for a square wave. So is 3 µs susbtantially less than 50 µs? You really should have been able to see this yourself.

Note that the datasheet you link to only shows the typical delay to be 2 µs at 10 mA input current and 100 Ω load. You can only guess what the worst case is, but it seems likely to be a small fraction of 50 µs in any case.

Yes, you can speed up the turn off time by adding a resistor between base and emitter of the output transistor. This comes at the expense of the current transfer ratio.

\$\endgroup\$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.