simulate this circuit – Schematic created using CircuitLab

From my analysis, and applying circuit theory, I find that Load(A) will have current flowing equal to 0.1Amps due to the PS, and the induced V1&V2 cancel out, without the use of a diode. However, there cannot be any induced-current from the induced-voltage source correct? They cancel out before that happens?

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    \$\begingroup\$ I've noticed that in all your 53 questions on SE.EE you have never marked one "accepted". Are you aware how to do this or is there some other reason? \$\endgroup\$ – Andy aka May 15 '15 at 18:33
  • \$\begingroup\$ No, not aware at all, how would I do that? \$\endgroup\$ – Pupil May 15 '15 at 18:57
  • \$\begingroup\$ You should really read the page rules if you will, before you register... Take a look at here: electronics.stackexchange.com/tour \$\endgroup\$ – Golaž May 15 '15 at 19:25
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    \$\begingroup\$ @Key - You press the check mark button under the up/down vote arrows to the left of the answer. \$\endgroup\$ – I. Wolfe May 15 '15 at 19:34

This cannot be analysed because you have an anomaly where the two induced voltages (net effect zero volts) is placed across a voltage source of 10 volts. This will cause infinite current to flow and makes it non-analysable.

Even if the two induced voltages were additive or anything that resulted in a net voltage other than 10V it produces infinite current.

With a voltage source (as shown) across a 100 ohm resistor, this part of the circuit can be taken in isolation and the current will be 0.2 amps.


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