# Mutual Inductance - Self Induced Voltage

When constructing mesh equations for each loop where two coils are linked, I know how to determine the polarity of the induced voltage by use of dot markings, but I need some clarification on the self induced voltage...

If I take the current as clockwise in each mesh, then $Ldi/dt$ for the self induced voltage will be positive where the current enters the inductor (like a resistor), right? So it'll be positive in both equations.

simulate this circuit – Schematic created using CircuitLab

I saw an example taking it as negative which is really bugging me. Is it a mistake, or...
(The example had the same configuration as above.)