# 4/5 band resistor - extra black band

I have two resistors which need to be replaced. I tried to determine the value, but it can't make sense of these black bands: For reference the bands are:

• brown - silver - green - brown - black
• brown - silver - red - brown - black

Since a silver line can only be part of the multiplier, that means the black line on the right has to be the tolerance. Black can not be used for a tolerance from what I've read.

Is this black line a tolerance value or something else?

• You are reading the color code in the wrong direction. The two big resistors are to be read right to left. The last (leftmost) band is a tolerance specifier. Normally silver by itself means 10% and gold 5%. – Olin Lathrop May 19 '15 at 17:36
• Thanks Olin. So then these are 0.15 and 0.12 ohm 1% resistors? – tehwalris May 19 '15 at 17:42
• @tehwalris Divide those numbers by 10 because of the leading zero. – Spehro Pefhany May 19 '15 at 17:47

I don't think I've ever seen a resistor value with a leading zero (usually those super-low values are marked with the value in numerals), but that's what those appear to be. 0.012$\Omega$ 1% and 0.015$\Omega$ 1% are what I see (reading from right to left, as Olin suggests, but I think the silver is a multiplier and the brown is the tolerance).
Here's a 0.015$\Omega$ 1% resistor (courtesy Digikey):