This sounds like a very straightforward question, and probably has an obvious answer. I've read a section in a physics book on electricity, I've read a textbook on DC and this simple concept seems to elude me.
Say I have this circuit (The one to the left):
It's about as simple as it can get. A voltage source connected to a resistor.
I've chosen these values for simplicity's sake. It's easy enough to use Ohm's Law to get the current running through the circuit:
$$I= .01A = 10mA$$
Okay, so now we know at any point we're getting 10mC/s through any point in the circuit.
But, with that interpretation, there is no voltage loss anywhere. If there is the same current everywhere, and the same circuit resistance everywhere, there is the same voltage...everywhere. Regardless of whether you're below, above, or parallel to whatever component your asking about.
But if this is true, voltage dividers wouldn't work, and current shunts wouldn't drop 100% of the voltage.
Ohm's Law seems counter-intuitive.
This circuit is a current shunt. It drops 100% of the voltage across it. That means that Node2 should be at, or electrically common to ground.
But, let's take the second circuit into consideration. Suppose SW1 is on. D1 will be on for short period of time until the capacitor is fully charged. When I disconnect the switch D1 will turn on through the charge stored on C1 at the rail voltage.
How is this possible? I'm having a very hard time understanding this simple concept...