I've read before that each 1 mm\$^2\$ of copper can handle up to 1 A. Is that true? Is there an easier formula than the one used on online calculators that requires temperature and such?
To give more details, I have 3 main points in my circuit where current is going to be at most 500 mA which are now unrelated (to make 1.5 A in total). My tracks' width is 0.02 in which is 0.5 mm. My width is going to be most likely 1 mm (or maybe less, depending on the etching equality which I cannot guarantee) so with my calculations I'll have around 0.5 A with no factor of safety.
My questions are:
- Are my calculations correct? Is there a better way to do them?
- Any tips or suggestions?