How to analyze this circuit with resistors and capacitors?

I have to find out the value of $V_{o}$ and $V_{c}$ initially and finally of the this circuit when $S_{1}$ and $S_{2}$ switches are simultaneously closed.

Edit: $V_{c}$ is across the capacitor $C_{1}$ and $V_{o}$ is across the resistor $R_{3}$.

My thought is:
Initially, $V_{c}=0V$

Using mesh analysis,
For first loop, $-25 + I_{1} + 0 +3(I_{1} - I_{2}) - 10 = 0$ $or, 4I_{1} - 3I_{2} = 35$
For second loop, $10 + 3(I_{2} - I_{1}) - 4I_{2} = 0$ $or, -3I_{1} + 7I_{2} = -10$
Solving these two equations, $I_{1} = 11.31mA$ and $I_{2} = 3.42mA$
Initially, $V_{o}=4I_{2}$ $or, V_{o} = 13.68V$

By substituting open circuit equivalent for the capacitor,
steady state value for the capacitor is, $V_{f} = 25V$

I am confused that the value of $t$ is not given. Then how i can calculate the voltage that is stored in capacitor. Also, how i can calculate the value of $RC$. Or I just have to assume that the capacitor is fully charged?

• V0 and Vc are missing from your diagram.
– JRE
Commented Jul 9, 2015 at 12:37
• 'finally' means $t=\infty$
– Chu
Commented Jul 9, 2015 at 12:46
• Aside from what JRE said, where is the reference node that you will measure $V_0$ and $V_c$ relative to? Commented Jul 9, 2015 at 16:26