I read that for DC electric motors you should generally use the motor with the highest "motor size constant" you can (motor size constant Km = Kt^2 / R, where Kt is motor torque constant i.e. N*m/A, and R is the resistance of the motor windings). Furthermore, Km is independent of motor windings since if you take a motor with 6 turns of parallel double wire and rewire it with 12 turns of single wire, this will double the Kt but quadruple the motor winding resistance by effectively doubling the length of the wire and halving the cross-sectional area. Thus if Km is the right evaluation criterion, then you should be indifferent between winding schemes for a given motor.
But this seems confusing to me in the context of a project I'm working on.
Lets say you have an electric vehicle and are trying to decide whether you should wind your motor with 6 turns of parallel double wire (6T-2W), or 12 turns single wire (12T-1W). You will choose your gearing so that your vehicle will have the same top speed regardless of winding. Since the Kv of the 6T-2W motor is twice that of the 12T-1W motor (Kv = motor velocity constant rpm/V, Kv = 1/Kt), if your gearing ratio for the 6T-2W setup is 1:1, your gearing ratio for the 12T-1W setup will be 1:2. At the wheels, the gearing perfectly offsets the effect of the winding scheme. Thus your vehicle speed and torque for a given applied voltage and current will be the same regardless of which winding scheme you use. However, the 12T-1W winding scheme will have 4x the winding resistance of the 6T-2W scheme, and will therefore generate more heat through copper losses and have a lower maximum current draw/torque output at the wheel. Doesnt this mean that even though the two winding schemes result in the same motor size constant Km, you should use the 6T-2W winding?