I'm working on a PCB for the MP2617. That IC integrates a buck converter and has two physical SW pins sandwiching the VIN pin, as shown in my tentative layout below. No other pins on the IC are doubled. So I'm wondering if the doubled SW pin is to increase the current capacity or just to provide more layout options. I should note that the device will be operating at the top end of its input voltage and step-down ratio capability (14 V to 3.6 V), and 2/3 of its output current rating of 3 A. The estimated inductor peak current is 2.5 A
- can I safely leave one of them unconnected?
- should I connect them together by a 10 mil trace inside the IC footprint (replacing the existing ground trace), even though it will come very close to the small signal pins on the right hand side, and the 10 mil trace will have little current capacity?
- should I connect them together by a trace and two vias on the left of the IC, at the cost of reducing the width of the PGND and VIN traces?
The datasheet is mute on that matter.