It might be a silly question since I am new to circuits and have little knowledge about it.
I've learned that gain of a current to voltage convertor with op-amp is determined by feedback resistor
R in the following figure:
Let's say I'm using an op-amp with GBWP of 10 MHz and using a feedback resistor of 47 kOhms. In this situation, will available bandwidth be 10M/47k = 212.xxx MHz ?
I am a bit confused that it is ok to regard it as a general concept of gain in other amplifying circuit.
In the figure above, gain is determined as
1 + R2 / R1 or
R2 / R1 which is generally and practically 0 < gain <= 100... something. It is much smaller than a resistance, 47 k.
Is what I said is correct, or am I missing something and there are something I didn't know?