# Calculating Transfer Function of passive circuit

I have the following passive circuit:

I want to calculate it's transfer function $V_{out}(s)/V_{in}(s)$.

My thoughts are: Part I: The voltage on the capacitor in the center (call it $V_c(s)$) is taken by the voltage divider created by the resistor and inductor in series to it's left and that capacitor i.e. $V_c(s)=V_{in}(s)(1/sC)/((1/sC)(R//sL))$ (these lines$\\$ mean that R and L are in parallel). Part II: Then since we have $V_c(s)$ which is of course a function of $V_{in}(s)$, we can calculate $V_{out}(s)$ from the voltage divider created by the rightmost resistor and the inductor on the left as$V_{out}(s)= V_c(s)(R)/(R+sL)$. Part III: Afterwards i substitude the expression of $V_c(s)$ that i calculated in part I and this way i find the expression for the transfer function $V_{out}(s)/V_{in}(s)$.

Are my ideas correct? If not what should i do? All ideas that can help me are welcome. Thanks in advance.