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I designed a circuit as shown in wikipedia:colpitts which runs at about 500kHz, L=680uH and C_1=C_2=100pF (+ some tuning caps in parallel to L). When looking at it with an oscilloscope it works just fine, now I want to decouple the signal from the oscillator (the scope's probe's capacity alters the frequency for example). What circuit would do that? I tried an emitter follower but as soon as the collector of the oscillator circuit "sees" a base, oscillation stops. I tried what resistance to GND would not influence the signal and found out that 100kOhm attenuate the oscillation to about half and 1MOhm may just be right. So I tried this(imagine all missing parts of the left bjt as in the link above):

schematic

simulate this circuit – Schematic created using CircuitLab

I tried some combinations of values of the resistors but nothing seemed to deliver the signal to output. Either it was destroyed right away (when R_B was low, no oscillation even occurred) or nothing came out of the transistor (when R_B was large, 10k-100k). Why is that? Can anyone propose a circuit that may buffer the signal for further use so to speak? Last but not least if anyone has an idea of how to reduce phase jitter of the oscillator itself, that would be great. Thanks

Edit: Hey I played around a bit. The emitter (as expected) has a lower impedance and is more loadable, but I put no transistor behind it yet as an amp stage because the signal is not as sinusoidal as the collector output (lower half waves are cut off partly). How can this be fixed?

To increase stability I tried to make a Clapp version out of my circuit by doing this:

schematic

simulate this circuit

Notice the cap in series with the inductor and the new large signal bias resistor. The stability did not increase. Did I do it right?

Since the emitter did not give enough sinusoidal a signal, I tried to lower R1 (4.7k down to 470 Ohm) to provide more current and therefore making the collector signal "stronger" (more loadable) but the circuit stopped working completely. How could this be predicted (is there a formula or something? All formulas for Colpitts I found are that gm*R_E > C1/C2 and the obligatory f_osc=1/(2pi sqrt(LC))). Is there some good paper about Colpitts with an extended mathematical approach?

Further more, which configuration is more stable (and if so, why?): common base or common collector? I looked at the ham radio circuits (and I am not through yet) but they seem to use mostly Colpitts in common collector configuration. Is that hinting to that this is more stable?

Attempts to decouple the source voltage more did not make the circuit more stable (more and closer caps of various capacities). Wrapping the whole circuit in aluminum foil did not help either (it only produced smoke:-). No, kiddin, that was not the point, it really didn't help...).

Thanks, tomorrow more tests.

Update: So I changed the large cap of 100nF (C3) to 100p and the feedback caps to 470p. Larger values didn't work (which I tried to make C3 the only frequency-defining cap, at least almost). The stability increased. What also increased the stability was to lower the base bias voltage almost to the point where the circuit stops oscillating. Further more the wave form got more clean a sinus. This was to expect, since we give only as little amplification as possible to sustain oscillation.

The circuit oscillates now at 655kHz and only changes slowly in the sub-10Hz region. My goal is to get an oscillator, which should be short-time stable and not wildly oscillate around its center frequency (so to speak, the frequency at which the frequency alters should be low...). I only have 200mVpp left at the emitter, but I think it can be loaded a little with a common emitter stage that amplifies the signal. So instead of an emitter follower there will be a common-emitter amplifier.

Surprisingly (to me...) a better coil with less resistance did have no effect on stability. Why?

If you are interested I will post some pictures and screenshots of the scope. Let me know.

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  • \$\begingroup\$ can you include the circuit of the oscillator itself? \$\endgroup\$ – Kevin White Aug 28 '15 at 2:14
  • \$\begingroup\$ Done, do you think R2 and R1 should be different? I started out with R2 =10k but that gave too little range at the output and cut off the signal to lower values. \$\endgroup\$ – jjstcool Aug 28 '15 at 20:43
  • \$\begingroup\$ You haven't really changed it to a Clapp oscillator because the 100nF cap is so much larger than the 100pF caps. In a Clapp the cap directly in series with the inductor is the main resonant cap. Also the way you have it configured the resonant current has to go through the power supply. Connect the inductor to ground. What do you mean by "not more stable". How are you measuring stability? \$\endgroup\$ – Kevin White Aug 30 '15 at 0:43
  • \$\begingroup\$ Yes I was wrong with the Clapp design. Change it later on. More stable means the frequency change. I mix it down with another oscillator so I have frequencies in the audible domain and when looking at it with my scope I see the frequency varying a lot. Here "a lot" is relative, since it is mixed down the frequency change of about 100Hz is a lot, although it is not so much for the 500kHz of the original oscillator. Is that clear? I will do some changes today and give you an update. Thanks \$\endgroup\$ – jjstcool Aug 30 '15 at 11:20
  • \$\begingroup\$ I updated what I did tonight. \$\endgroup\$ – jjstcool Sep 2 '15 at 3:37
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If you alter your diagram to look more like this it should work:

enter image description here

In your diagram, instead of a voltage divider and a capacitor you only have a single resistor. This won't work because the output of the Colpitts oscillator dips below 0.6 volts, and anything less than ~0.6V won't be picked up by an NPN transistor.

In the diagram, you can see that I've coupled the output of the oscillator with C2 to a voltage divider, with R1 and R2. The voltage divider adds a DC offset of 9V to the base of Q2. This way, the voltage at the base now ranges from 3V to 15 volts instead of -6V to 6V. Since the signal is always above 0.6V, Q2 passes it.

The output uses C1 to decouple the DC from the sine wave, leaving you with your original 6V amplitude sine wave, just with amplified current.

You can change the values of some of the components around if you want, but C2 should optimally be around 1/(2*pi*500KHz*R2), and C1 around 1/(2*pi*500KHz*R3).

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  • \$\begingroup\$ In case the input impedance of the follower (because of R1 and r2) is too large you can increase this impedance using the bootstrap principle. \$\endgroup\$ – LvW Aug 28 '15 at 10:58
  • \$\begingroup\$ Thanks for the answer but the amplitude is not 6V (where did you get that from? Did you simulate it?) nor did I have a cap in series from collector to base. I know the concept you're proposing, but I saw no use in using a cap to lose the DC and then adding a new DC with (in your schematic) R1 and R2 when the amplitude of the oscillators signal is from about 2V to 16V (when not loaded). My question aims more into the direction why a light load as an emitter follower shuts down oscillation. But I'll try this anyway and tell keep you up about it. Thanks \$\endgroup\$ – jjstcool Aug 28 '15 at 20:58
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What is the load on the output?

That will affect the value if R2 - it has to be low enough to drive the output on the negative going edge.

As the other Kevin mentions you need to get the right bias conditions for the buffer transistor.

Rather than feeding it from the collector of the oscillator you could connect it to the emitter which is a lower impedance point. You could go even further and split c3 into 2 capacitors to tap down the impedance even further - the lower the better at the expense of output voltage swing. For example replace C3 with two 200pF caps in series with the junction feeding the buffer. Something like this circuit.

schematic

simulate this circuit – Schematic created using CircuitLab

To improve the stability of the oscillator the first thing is to give it a good power supply. Use a lot of decoupling and separate it from other circuitry probably with its own regulator.

Another improvement to the Colpitt's oscillator is the Clapp oscillator that has an additional capacitor in series with the inductor to do this isolation. This isolates the transistor form the resonant circuit and avoids parameter variations in the transistor from affecting the oscillation frequency.

(The component values in this schematic are just intended as an example - I have not calculated them to meet your needs).

schematic

simulate this circuit

You should research the oscillators used in ham radios - often referred to as VFOs. There are a number of circuit techniques used to provide good stability.

Here is a link to a description; Clapp Oscillator

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  • \$\begingroup\$ Ah thanks, these are two very good ideas. I will try it out and give you guys some feedback soon. \$\endgroup\$ – jjstcool Aug 28 '15 at 21:36
  • \$\begingroup\$ See my edit in the original post. \$\endgroup\$ – jjstcool Aug 29 '15 at 23:05

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