I've never seen such connection before and I was wondering why the diode is grounded in that configuration.

enter image description here

  • \$\begingroup\$ Inductive kickback? Perhaps there is some load with inductance conencted to it. \$\endgroup\$ – Marko Buršič Aug 28 '15 at 14:37
  • \$\begingroup\$ Given the 15 A rating, I'd guess the diode has an extra pad for thermal reasons. \$\endgroup\$ – The Photon Aug 28 '15 at 14:42

See the datasheet of the diode : SBR15A30SP5

You have 3 pins for the Diode: enter image description here

The Left Pin and the Right Pin must be connected to the printed circuit board. In your case they are connected to the ground.

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  • \$\begingroup\$ Please explain how this answer actually answers the question \$\endgroup\$ – Funkyguy Aug 28 '15 at 14:43
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    \$\begingroup\$ Actually it answers it very well. \$\endgroup\$ – Eugene Sh. Aug 28 '15 at 14:44
  • \$\begingroup\$ @Funkyguy This question can be interpreted in two different ways: 1) Why is the diode configured so that the cathode is on the 3.3V line and the anode on the ground line (I think this is how you read it). 2) Why does the diode have two connections to ground? codo provides the answer to the second question (which is how I interpreted the initial request) \$\endgroup\$ – DerStrom8 Aug 28 '15 at 14:47
  • \$\begingroup\$ @derstrom8 Ah I see, I interpreted it as the first one. Which one does OP want? \$\endgroup\$ – Funkyguy Aug 28 '15 at 14:48
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    \$\begingroup\$ @Funkyguy which one indeed. That is still unknown to me--I'm not sure which one he's looking for, but there are answers for both. He should have his answer one way or another =) \$\endgroup\$ – DerStrom8 Aug 28 '15 at 15:03

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