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Resistors R2,R3,R4 are connected in series. I'm not sure how to find the equivalent resistance of between terminals A and B, because of the short circuit. However, I suspect the answer is R1+R4 because of the short circuit. I am confused about this, can someone help me? Thanks!

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EDIT: Thanks for pointing that out. My drawing is indeed incorrect. Lets say the resistor R4 which is connected in series to R2, R3 will now be called R5

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If your drawing is correct, then the resistance between A & B is simply R1 + R4. R2, R32 and R4 are not relevant since they are shorted out. Note, however, that there are 2 resistors with the same label, R4.

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  • \$\begingroup\$ is correct. Just as an exercise you can consider the short to be a resistor of almost 0 resistance. eg. 0.00001ohm then use the parrallel resistance rule to calculate the total resistance for that segment (R0-R2-R3-R5. The result should show that the combined resistance will be virtually the same as 0.00001ohm thereby proving you can ignore the R2-R3-R5 leg in this case. \$\endgroup\$ – BenG Sep 12 '15 at 21:43

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