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If I had a 10 amps of current that was split down two wires, one with 1 ohms of resistance and another with 2 ohms of resistance, what equation would I use to determine how much charge went down each wire?

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    \$\begingroup\$ You are looking for a current divider. \$\endgroup\$ – Null Sep 19 '15 at 1:27
  • \$\begingroup\$ The given answer is correct as long as both of your wires actually form a closed circuit (they are not open ended). \$\endgroup\$ – Kurt E. Clothier Sep 19 '15 at 2:06
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Since the resistance ratio between the wires is 2:1 so will be the current. ie 3.3A:6.6A.

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  • \$\begingroup\$ So it's just the ratio between the resistances? \$\endgroup\$ – Lurk21 Sep 19 '15 at 1:24
  • \$\begingroup\$ correct. With the lower resistance taking the larger current. Lookup Kirchoffs Current Law for details. But essentially current into a node (in this case the end of your wires where they meet) must equal the current out. So 10A in must eq 10A out. \$\endgroup\$ – BenG Sep 19 '15 at 1:28
  • \$\begingroup\$ That's awesome. \$\endgroup\$ – Lurk21 Sep 19 '15 at 1:30
  • \$\begingroup\$ If you wish to use an equation. Consider that the circuit you have is basically 2 resistors in parrallel. In a parrallel circuit the voltage applied to the two resistors will be equal. So if you use Ohms law I=V/R then you can work out the actual current. It should be the same values as above. \$\endgroup\$ – BenG Sep 19 '15 at 1:36
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    \$\begingroup\$ @Lurk21 It is not "just ratio between the resistances". It is just the equal voltage across the resistances that are connected in parallel. \$\endgroup\$ – Nick Alexeev Sep 19 '15 at 2:49

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