# Nodal Analysis - Deriving equations at each node

I've recently come across a question where I need to solve using Nodal Analysis:

I'm a bit confused about the part where the arrow V1 points in the opposite direction to the voltage source. I've worked on the question and this is what I've come with so far (all in polar form):

I1 = I2 + I3

I4 = I3 + I5

I1 = (10/_0 - V1) 2

I2 = (10/_30 - V1) j5

I3 = (V1 - V2) (4 + j4)

I4 = (V2) (6 - j8)

I5 = (5/_0 - V2) (5)

And my nodal equations look like this:

At node 1 (Polar Form):

$$\sqrt{3}*90^\circ = V_1(\frac{3\sqrt{10}}{40}*18.43495^\circ) - V_2(\frac{\sqrt{2}}{8}*-45^\circ)$$

At node 2 (Polar Form):

$$1*0^\circ = -V_1(\frac{\sqrt{2}}{8}*-45^\circ) + V_2(0.3867*-6.6666599^\circ)$$

Would this be correct? And does the direction of arrow V1 have any significance?

• I see nothing wrong with the arrows. You can declare $V_1$ etc. to be wherever you wish. – Chu Sep 28 '15 at 0:03

For example, here I've removed those arrows, renamed nodes with lowercase letters, and designated a ground node at the bottom. Do all your analysis using Va, Vb, Vc, Vc, Vd, and Ve. Branch currents are assumed to follow the direction of the arrow on the branch (I1, I2, I3, I4, and I5).