To add a little bit to the accepted answer: in real life, the voltage after the 1 ohm resistor will not equal the voltage before it for only a split second during the charging of the circuit, when you first turn on the 32V source, or for the split second just after you ground the 32V source. The reason is because during these short transient times, "a" is charging up through the resistor (since it has a tiny bit of capacitance..as all wires and conductors do in real life), so a tiny current does exist. Once "a" is charged, and you reach the steady-state condition, the current ceases and the voltage on each side of the 1 ohm resistor is the same.
In theory, "a" has no capacitance, so you can ignore the above real-life situation. :)
The point, however, is that in this case, the real-life steady-state solution is the same as the theoretical one, though the real-life transient solution is momentarily different.
Now, the above is just some extra info. For the most direct and correct answer, see "The Photon"'s answer.