Parallel RLC circuit

I am beginning to learn AC circuits and am trying to analyze the following RLC circuit: I want to find the real-time voltage across the resistor. I believe I will do this by finding the current with I = V_p / Z then use that current to find the voltage on the resistor. I'm not sure how to calculate Z in a parallel circuit. Would I do Z = (1/(Z_R + Z_C) + 1/Z_L)^-1 as I would with resistors in parallel?

• There's a voltage divider formed by R and C, so no need to bother with L – Chu Sep 30 '15 at 19:58
• Paraphrasing @chu, you have a perfect voltage source that puts a 141.42V RMS sinewave across the series combination of R1 and C2 - the inductor is nothing to do with finding the voltage across R1. – Andy aka Sep 30 '15 at 21:08
• Okay, I understand that. How do I then only deal with R1 then? I'm a little confused on AC circuits. – TheStrangeQuark Sep 30 '15 at 21:13
• @Andyaka and does that mean there is no current going through L1? – TheStrangeQuark Sep 30 '15 at 21:14
• The same voltage appears across L, and the series combination of R & C. You can apply Ohm's Law to both of these branches separately to work out the currents through them. But to work out the voltage across R you only need to treat R and C as a voltage divider - no need to find the current and then multiply by R. – Chu Sep 30 '15 at 21:49