I would like to look at negative resistance from a practical point of view, not just theory. Would you answer my questions,please?
The op-amp, R1, R2, and R3 behave as a negative resistance: Rn = - 100 ohms.
R4 is in series with the negative resistance.
1- If I constructed this circuit on a breadboard, Will the negative resistor work as a generator and injects current through AA batteries and damage them? Or the current just stops?
2- If the supply was a transformer with bridge rectifier, Would the bridge rectifier prevent the current form interning the supply?
3- If the op-amp IC is supplied with 12 volts or any value that is different from input voltage, Will that affect any parts of the circuit ?
4- If I changed the value of R4 to be 150 ohms, The current will be:
V = I*R
I = 0.1 A , Is that right ?
Rn is the equivalent negative resistance, on of its terminals appears at the non inverting input of the op-amp and the other terminal appears at the ground.
What I mean by AA batter or transformer is we remove the 5 volts supply and put an AA battery or a transformer instead.
I think the output terminal is also the non inverting input because the circuit behave just like a resistance.
For more information about negative impedance converter :https://en.wikipedia.org/wiki/Negative_impedance_converter