I know how to find resistance, current, and voltage through series/parallel circuits. The problem I'm having is figuring which part of this circuit to simplify first. What is the correct order of operations for each branch? Or how can I redraw this circuit to make more sense?
2 Answers
Like the users before me pointed out, you can solve it just by redrawing the circuit, and noticing a balanced wheatstone bridge.
The problem is that using standard series parallel transformations does not work in this case. You have 3 options. Kirchhoff's current rule, Kirchhoff's voltage rule, Y/Delata transform.
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\$\begingroup\$ Instead of getting all the laws out already, why not simply look at the circuit and examine what's actually happening ? Maybe no laws are needed ? \$\endgroup\$ Oct 1, 2015 at 10:02
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\$\begingroup\$ I'm going to look at some examples with these rules and be back later. \$\endgroup\$– srp009Oct 1, 2015 at 10:18
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\$\begingroup\$ What if I say: there is NO NEED to use any of the laws or rules ??? Why does no one try to "see" what this circuit is doing ? I must have a special gift to see that the voltage across the resistor in the middle is 0V. So on the left there's 2 x 4 = 8 ohms and on the right there's 4 x4 = 16 omhs. 8 and 16 in parallel gives: 5 1/3 ohm. 12V / 5.33 = 2.25 A There, solved no Kirchoff, Thevenin or Wheatstone needed. \$\endgroup\$ Oct 1, 2015 at 12:50
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\$\begingroup\$ Thanks. So the R3 in the middle is a dead end with 0V and 0I ? and you just have to calculate the series/parallel like that middle R3 resister inst there? \$\endgroup\$– srp009Oct 1, 2015 at 16:00