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I am looking for a way to use a MOSFET as a normally closed switch such that when a battery charger is attached it opens the switch to disconnect the battery from the rest of the circuit. I want the load to be between the MOSFET source and ground, instead of between the battery and the MOSFET drain.

EDIT: I want the load of the battery to be disconnected. Thus the battery is only connected to the charger. The battery is a single cell LiPo and the charger will be built into the board so just charging power is needed to charge the battery.

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    \$\begingroup\$ Just go ahead and do it. \$\endgroup\$ – PlasmaHH Oct 27 '15 at 21:09
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    \$\begingroup\$ If you want the battery to be disconnected when the battery charger attaches, how on earth is it going to charge the battery. Now c'mon, what do you really want!! \$\endgroup\$ – Andy aka Oct 27 '15 at 21:21
  • \$\begingroup\$ I assume that he means he wants to disconnect the battery from the circuit that it would otherwise be powering the circuit... Maybe? \$\endgroup\$ – Matt Ruwe Oct 27 '15 at 21:22
  • \$\begingroup\$ There have been questions about this type of thing before, just browse through them and you will most probably find what you need. Maybe even with a couple of diodes. \$\endgroup\$ – Bimpelrekkie Oct 27 '15 at 21:22
  • \$\begingroup\$ I'd be hesitant to put diodes between a battery and its charger. Simple chargers won't care, but they'd have to be specially designed to account for the diode drop. Complex chargers would get really confused as the battery disappears and reappears depending on what part of the algorithm they're in. \$\endgroup\$ – AaronD Oct 27 '15 at 21:25
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Look at depletion-mode FET's. They're on by default and require some gate voltage to turn off.

Where an enhancement N-channel requires positive voltage to turn on, a depletion N-channel requires negative voltage to turn off. Similar relation between P-channels.

I'll leave the construction details to the student.

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    \$\begingroup\$ But you will have a hard time finding a depletion type mosfet that will operate like a decent switch. Uhm, I'd be surprised if you can find any. All switching mosfets are enhancement fets. \$\endgroup\$ – Bimpelrekkie Oct 27 '15 at 21:20
  • \$\begingroup\$ True, but I gave him what he asked for: default on, forced off. He should read the datasheets anyway. \$\endgroup\$ – AaronD Oct 27 '15 at 21:23
  • \$\begingroup\$ @FakeMoustache -- there are depletion N-channel FETs out there that can be pressed into switching service in a pinch, see the Microchip/Supertex LND01 for an example. \$\endgroup\$ – ThreePhaseEel Oct 27 '15 at 22:45
  • \$\begingroup\$ @ThreePhaseEel OK, then I'll have to eat my hat ;-) Not a very low Rdson though (1.4 ohms) :-( \$\endgroup\$ – Bimpelrekkie Oct 28 '15 at 10:07
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You could try to use some Schimmit Trigger CI to invert the drain input signal, so when its input is low, the output will put high, and vice-versa. This basically "invert" your transistor gate. Look at some CD40106/74LS14 datasheet and see if they fit in your application. `

https://www.fairchildsemi.com/datasheets/CD/CD40106BC.pdf https://www.egr.msu.edu/eceshop/Parts_Inventory/datasheets/74ls14.pdf

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